How many `176 Omega` resistors (in parallel) are required to carry 5 A in 220 V line ?

Explanation

For x number of resistance `176 Omega`, the equivalent resistance of the resistors connected in parallel is given by Oh,'s law as V=IR
R= V/I
Where,
Supply voltage, V= 220 V
Current, I=5 A ltbr gt Equivalent resistance of the combination = R, given as
`1/R=x xx(1/176)`
`R=(176)/x`
From Ohm's law,
`V/I=(176)/x`
`x=(176 xx I)/V=(176xx5)/(220)=4`
Therefore, four resistor of `176 Omega` are required to draw the given amount of current.