Compare the acidic strength of the following
`(a) CHF_(3)`
`(b) CHCl_(3)`
`(c )CHBr_(3) (p pi - dpi " bonding in Br is not as much as effective as in Cl due to large size of Br ")`

Explanation

To compare the acidic strength of the compounds CHF₃, CHCl₃, and CHBr₃, we need to analyze the stability of the corresponding anions formed when these compounds lose a hydrogen ion (H⁺). The acidic strength is directly related to the stability of the anion formed.

### Step-by-Step Solution:

1. **Identify the Anions**:
- When CHF₃ loses H⁺, it forms the anion CF₃⁻.
- When CHCl₃ loses H⁺, it forms the anion CCl₃⁻.
- When CHBr₃ loses H⁺, it forms the anion CBr₃⁻.
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