Write the correct order of acidic strength of following compounds:
`(a)CH_(3) - CH_(2)-O-H" "(b)CH_(3)-underset(CH_(3))underset(|)CH- O - H `
`(c)CH_(3) - underset(CH_(3))underset(|)overset(CH_(3))overset(|)C - O - H `

Answer

To determine the correct order of acidic strength of the given compounds, we need to analyze the stability of their conjugate bases after the removal of the acidic hydrogen (H⁺). The more stable the conjugate base, the stronger the acid.

### Step-by-Step Solution:

1. **Identify the Compounds**:
- (a) CH₃-CH₂-O-H (Ethanol)
- (b) CH₃-CH(CH₃)-O-H (Isopropanol)
- (c) CH₃-C(CH₃)(CH₃)-O-H (Tert-Butanol)

2. **Form the Conjugate Bases**:
- For (a): Remove H⁺ → CH₃-CH₂-O⁻ (Conjugate base of ethanol)
- For (b): Remove H⁺ → CH₃-CH(CH₃)-O⁻ (Conjugate base of isopropanol)
- For (c): Remove H⁺ → CH₃-C(CH₃)(CH₃)-O⁻ (Conjugate base of tert-butanol)

3. **Analyze the Stability of Conjugate Bases**:
- The stability of the conjugate base is influenced by the inductive effect (I effect) from alkyl groups. Alkyl groups are electron-donating, which can destabilize the negative charge on the oxygen atom.
- **(a)** Ethanol's conjugate base (CH₃-CH₂-O⁻) has two alkyl groups contributing to stability.
- **(b)** Isopropanol's conjugate base (CH₃-CH(CH₃)-O⁻) has three alkyl groups, which increases the electron density around the negatively charged oxygen, making it less stable than ethanol's conjugate base.
- **(c)** Tert-butanol's conjugate base (CH₃-C(CH₃)(CH₃)-O⁻) has four alkyl groups, which further increases the electron density, making it the least stable among the three.

4. **Determine the Order of Acidity**:
- Since the stability of the conjugate base is inversely related to the acidity of the original compound, the order of acidic strength will be the opposite of the stability of the conjugate bases.
- Therefore, the order of acidic strength is:
- (a) > (b) > (c)

### Final Answer:
The correct order of acidic strength is:
**(a) > (b) > (c)**