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In the reaction Br(2) +Na(2) CO(3) rar...

In the reaction
`Br_(2) +Na_(2) CO_(3) rarr NaBr + NaBrO_(3) + CO_(2)`
The equiv. wt. of `NaBrO_(3)` is

A

`("Mol. wt")/(1)`

B

`("Mol. wt")/(10)`

C

`("Mol. wt")/(5)`

D

`("Mol. wt")/(4)`

Text Solution

Verified by Experts

The correct Answer is:
C
x-factor for formation of `NaBrO_(3) = + 5`
`:. ` Equiv. wt. of `NaBrO_(3) = ("Mol.wt.")/(5)`
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