0.45 gm of an acid with molecular mass 90 g/mole is neutralized by 20 ml of 0.5 N caustic potash. The basicity of the acid is :

Options

A. 1
B. 2
C. 3
D. 4

Answer

B

Explanation

20 ml of 0.5 ( N) caustic potash `:. 20 xx 0.5 xx 10^(-3)` equiv. of acid = 0.45 gm
`:.` 1 equiv. of acid `= ( 0.45)/( 10 xx 10^(-3)) = 45` gm
`:.` x for acid `= ( 90)/( 45) =2 `
Hence, basicity of acid =2