Oxidation number of Ni in `Ni(CO)_(4)` is-

Options

A. 0
B. 4
C. 8
D. 2

Answer

To find the oxidation number of nickel (Ni) in the complex Ni(CO)₄, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Components of the Complex**:
The complex Ni(CO)₄ consists of one nickel atom and four carbon monoxide (CO) ligands.

2. **Determine the Charge of the Ligands**:
Carbon monoxide (CO) is a neutral ligand. This means that each CO contributes a charge of 0.

3. **Set Up the Equation**:
Let the oxidation number of nickel be represented as \( x \). Since there are four CO ligands, the total contribution from the ligands to the charge is \( 4 \times 0 = 0 \).

4. **Write the Charge Balance Equation**:
The overall charge of the complex is neutral (0). Therefore, we can set up the equation:
\[ x + (4 \times 0) = 0 \]
Simplifying this gives:
\[ x + 0 = 0 \]

5. **Solve for \( x \)**:
From the equation, we find:
\[ x = 0 \]

6. **Conclusion**:
The oxidation number of nickel in Ni(CO)₄ is 0.

### Final Answer:
The oxidation number of Ni in Ni(CO)₄ is **0**.