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N(2) + 3 H(2) rarr 2NH(3) Molecular we...

`N_(2) + 3 H_(2) rarr 2NH_(3)`
Molecular weight of `NH_(3)` and `N_(2)` are `x_(1)` and `x_(2)`, respectively. Their equivalent weights are `y_(1)` and `y_(2)`, respectively. Then `(y_(1) - y_(2))`

A

`((2x_(1) - x_(2))/( 6))`

B

`(x_(1) - x_(2))`

C

`( 3x_(1) - x_(2))`

D

`( x_(1) - 3x_(2))`

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The correct Answer is:
A
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MOTION-OXIDATION & REDUCTION -OXIDATION NUMBER ( EXERCISE -1)
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