0.115gm of sodium metal was dissolved in 500ml of the solution in distilled water. The normality of the solution would be -

Options

A. 0.010N
B. 0.0115N
C. 0.023N
D. 0.046N

Answer

To calculate the normality of the sodium solution, we will follow these steps:

### Step 1: Identify the given data
- Mass of sodium (solute) = 0.115 g
- Volume of solution = 500 mL

### Step 2: Convert the volume of the solution from mL to L
To convert mL to L, we use the conversion factor:
\[ \text{Volume in L} = \frac{\text{Volume in mL}}{1000} = \frac{500 \text{ mL}}{1000} = 0.5 \text{ L} \]

### Step 3: Calculate the equivalent mass of sodium
The molecular mass of sodium (Na) is approximately 23 g/mol. Since sodium is a monovalent ion (Na⁺), its equivalent mass is equal to its molecular mass:
\[ \text{Equivalent mass of Na} = \frac{\text{Molecular mass}}{\text{Valency}} = \frac{23 \text{ g/mol}}{1} = 23 \text{ g/equiv} \]

### Step 4: Calculate the number of equivalents of sodium
To find the number of equivalents, we use the formula:
\[ \text{Number of equivalents} = \frac{\text{Mass of solute}}{\text{Equivalent mass}} = \frac{0.115 \text{ g}}{23 \text{ g/equiv}} \approx 0.005 \text{ equiv} \]

### Step 5: Calculate the normality of the solution
Normality (N) is defined as the number of equivalents of solute per liter of solution:
\[ \text{Normality} = \frac{\text{Number of equivalents}}{\text{Volume of solution in L}} = \frac{0.005 \text{ equiv}}{0.5 \text{ L}} = 0.01 \text{ N} \]

### Final Answer
The normality of the solution is **0.01 N**.

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