100ml of 0.3 N HCl is mixed with 200ml of 0.6 N `H_(2)SO_(4)`. The final normality of the resulting solution will be -

Options

A. 0.1N
B. 0.2N
C. 0.3N
D. 0.5N

Answer

To find the final normality of the resulting solution when mixing 100 ml of 0.3 N HCl with 200 ml of 0.6 N H₂SO₄, we can follow these steps:

### Step 1: Calculate the milliequivalents of HCl
The formula to calculate milliequivalents (mEq) is:
\[ \text{mEq} = \text{Normality (N)} \times \text{Volume (ml)} \]

For HCl:
- Normality (N) = 0.3 N
- Volume = 100 ml

Calculating:
\[ \text{mEq of HCl} = 0.3 \, \text{N} \times 100 \, \text{ml} = 30 \, \text{mEq} \]

### Step 2: Calculate the milliequivalents of H₂SO₄
Using the same formula for H₂SO₄:
- Normality (N) = 0.6 N
- Volume = 200 ml

Calculating:
\[ \text{mEq of H₂SO₄} = 0.6 \, \text{N} \times 200 \, \text{ml} = 120 \, \text{mEq} \]

### Step 3: Calculate the total milliequivalents
Now, we add the milliequivalents from both solutions:
\[ \text{Total mEq} = \text{mEq of HCl} + \text{mEq of H₂SO₄} \]
\[ \text{Total mEq} = 30 \, \text{mEq} + 120 \, \text{mEq} = 150 \, \text{mEq} \]

### Step 4: Calculate the total volume of the solution
Now, we find the total volume of the mixed solution:
\[ \text{Total Volume} = 100 \, \text{ml} + 200 \, \text{ml} = 300 \, \text{ml} \]

### Step 5: Calculate the final normality
Finally, we can calculate the final normality (N) of the resulting solution using the formula:
\[ \text{Final Normality} = \frac{\text{Total mEq}}{\text{Total Volume (ml)}} \]
\[ \text{Final Normality} = \frac{150 \, \text{mEq}}{300 \, \text{ml}} = 0.5 \, \text{N} \]

Thus, the final normality of the resulting solution is **0.5 N**.

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