10ml of N-HCl 20ml of `N//2 ` `H_(2)SO_(4)` and 30 ml of `N//3` `HNO_(3)` are mixed together and volume made to one litre. The normality of the resulting solution is -

Options

A. `3N//100`
B. `N//10`
C. `N//20`
D. `N//40`

Answer

To find the normality of the resulting solution when mixing 10 ml of N-HCl, 20 ml of N/2 H₂SO₄, and 30 ml of N/3 HNO₃, we can follow these steps:

### Step 1: Calculate Milliequivalents for Each Acid
1. **For HCl:**
- Normality (N) = 1 N
- Volume (V) = 10 ml
- Milliequivalents (mEq) = Normality × Volume = 1 N × 10 ml = 10 mEq

2. **For H₂SO₄:**
- Normality (N) = 1/2 N
- Volume (V) = 20 ml
- Milliequivalents (mEq) = Normality × Volume = (1/2) N × 20 ml = 10 mEq

3. **For HNO₃:**
- Normality (N) = 1/3 N
- Volume (V) = 30 ml
- Milliequivalents (mEq) = Normality × Volume = (1/3) N × 30 ml = 10 mEq

### Step 2: Calculate Total Milliequivalents
- Total Milliequivalents = Milliequivalents of HCl + Milliequivalents of H₂SO₄ + Milliequivalents of HNO₃
- Total Milliequivalents = 10 mEq + 10 mEq + 10 mEq = 30 mEq

### Step 3: Calculate Normality of the Resulting Solution
- The total volume of the resulting solution after mixing is made up to 1 liter (1000 ml).
- Normality (N) = Total Milliequivalents / Total Volume (in liters)
- Normality = 30 mEq / 1000 ml = 30 mEq / 1000 ml = 0.03 N

### Final Result
The normality of the resulting solution is **0.03 N**.

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