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2 gm of a base whose equiv wt. is 40 rea...

2 gm of a base whose equiv wt. is 40 reacts with 3 gm of an acid. The equiv wt. of the acid is -

A

40

B

60

C

10

D

80

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AI Generated Solution

The correct Answer is:
To find the equivalent weight of the acid that reacts with 2 g of a base (equivalent weight = 40) and 3 g of the acid, we can follow these steps: ### Step 1: Understand the concept of equivalents In a neutralization reaction between an acid and a base, the number of equivalents of the acid will equal the number of equivalents of the base. ### Step 2: Calculate the number of equivalents of the base The number of equivalents of the base can be calculated using the formula: \[ \text{Number of equivalents} = \frac{\text{mass of the substance (g)}}{\text{equivalent weight (g/equiv)}} \] For the base: \[ \text{Number of equivalents of base} = \frac{2 \, \text{g}}{40 \, \text{g/equiv}} = 0.05 \, \text{equiv} \] ### Step 3: Set up the equation for the acid Since the number of equivalents of the acid will equal the number of equivalents of the base, we can set up the equation: \[ \text{Number of equivalents of acid} = \text{Number of equivalents of base} = 0.05 \, \text{equiv} \] ### Step 4: Calculate the equivalent weight of the acid Using the formula for the number of equivalents for the acid: \[ \text{Number of equivalents of acid} = \frac{\text{mass of acid (g)}}{\text{equivalent weight of acid (g/equiv)}} \] Substituting the known values: \[ 0.05 \, \text{equiv} = \frac{3 \, \text{g}}{\text{equivalent weight of acid}} \] ### Step 5: Rearranging to find the equivalent weight of the acid Rearranging the equation gives us: \[ \text{equivalent weight of acid} = \frac{3 \, \text{g}}{0.05 \, \text{equiv}} = 60 \, \text{g/equiv} \] ### Final Answer: The equivalent weight of the acid is **60 g/equiv**. ---
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