Consider the following statements Reaction
`KIO_(3) + 5Kl + 6HCl = 3I_(2) + 6KCl + 3H_(2)O`
( a) Kl is oxidise in `I_(2)`
(b) `KIO_(3) `, is oxidise in `I_(2)`
( c ) `KIO_(3)`, is reduced in `I_(2)`
(d) Oxidation number ( - 1) of I in KI is increased up to zero in `I_(2)`
Of the following statements

Options

A. a,c and d are correct
B. a,b and d are correct
C. b and d are correct
D. only a is correct

Answer

To analyze the given reaction and determine which statements are correct, we will follow these steps:

### Step 1: Write the Reaction
The reaction provided is:
\[ \text{KIO}_3 + 5 \text{KI} + 6 \text{HCl} \rightarrow 3 \text{I}_2 + 6 \text{KCl} + 3 \text{H}_2\text{O} \]

### Step 2: Determine Oxidation States
We need to find the oxidation states of iodine in each compound involved in the reaction.

1. **In KIO3:**
- Potassium (K) = +1
- Oxygen (O) = -2 (3 O atoms contribute -6)
- Let the oxidation state of iodine (I) be \( x \).
- The compound is neutral: \( +1 + x - 6 = 0 \)
- Therefore, \( x = +5 \).

2. **In KI:**
- Potassium (K) = +1
- Iodine (I) = -1

3. **In I2:**
- Iodine (I) = 0 (as it is in elemental form).

4. **In KCl:**
- Potassium (K) = +1
- Chlorine (Cl) = -1

5. **In H2O:**
- Hydrogen (H) = +1 (2 H contribute +2)
- Oxygen (O) = -2

### Step 3: Identify Changes in Oxidation States
Now, we will analyze the changes in oxidation states during the reaction:

- **KIO3:** Iodine changes from +5 to 0 (reduction).
- **KI:** Iodine changes from -1 to 0 (oxidation).

### Step 4: Evaluate Each Statement
Now we will evaluate the statements based on our findings:

(a) **KI is oxidized to I2**:
- This statement is **correct** because iodine in KI goes from -1 to 0, indicating oxidation.

(b) **KIO3 is oxidized to I2**:
- This statement is **incorrect** because KIO3 is reduced (oxidation state decreases from +5 to 0).

(c) **KIO3 is reduced to I2**:
- This statement is **correct** because KIO3 is reduced (oxidation state decreases from +5 to 0).

(d) **The oxidation number (-1) of I in KI is increased to 0 in I2**:
- This statement is **correct** because the oxidation state of iodine increases from -1 in KI to 0 in I2.

### Conclusion
The correct statements are (a), (c), and (d). Therefore, the answer is that options A, C, and D are correct.