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Select the pair of oxidation processes, ...

Select the pair of oxidation processes,
(a) `2Cu^(2+) rarr Cu_(2)^(2+)`
( b) `MnO_(4)^(-) rarr Mn^(2+)`
( c ) `[Fe(CN)_(6) ]^(-4) rarr [ Fe(CN)_(6)]^(-3)`
( d) `2I^(-) rarr I_(2)`

A

a,b

B

c,d

C

a,d

D

b,c

Text Solution

AI Generated Solution

The correct Answer is:
To determine the pair of oxidation processes from the given options, we need to analyze each reaction and identify whether oxidation (loss of electrons or increase in oxidation state) is occurring. ### Step-by-Step Solution: 1. **Analyze Option (a): `2Cu^(2+) → Cu_(2)^(2+)`** - The oxidation state of Cu in `Cu^(2+)` is +2. - In `Cu_(2)^(2+)`, the overall charge is +2, which indicates that the oxidation state of Cu is effectively +1 (since there are two Cu atoms). - Since the oxidation state decreases from +2 to +1, this is a reduction process, not oxidation. **Conclusion**: This is not an oxidation process. 2. **Analyze Option (b): `MnO_(4)^(-) → Mn^(2+)`** - In `MnO_(4)^(-)`, the oxidation state of Mn can be calculated as follows: - Let the oxidation state of Mn be x. - The total charge from 4 oxygen atoms is -8 (4 * -2). - The overall charge of the ion is -1, so: \[ x - 8 = -1 \implies x = +7 \] - In `Mn^(2+)`, the oxidation state of Mn is +2. - The oxidation state decreases from +7 to +2, indicating a reduction process. **Conclusion**: This is not an oxidation process. 3. **Analyze Option (c): `[Fe(CN)_(6)]^(-4) → [Fe(CN)_(6)]^(-3)`** - In `[Fe(CN)_(6)]^(-4)`, the overall charge is -4. - The charge of 6 cyanide ions (CN^-) is -6, so: - Let the oxidation state of Fe be x: \[ x - 6 = -4 \implies x = +2 \] - In `[Fe(CN)_(6)]^(-3)`, the overall charge is -3. - The charge of 6 cyanide ions remains -6, so: - The oxidation state of Fe is: \[ x - 6 = -3 \implies x = +3 \] - The oxidation state increases from +2 to +3, indicating an oxidation process. **Conclusion**: This is an oxidation process. 4. **Analyze Option (d): `2I^(-) → I_(2)`** - The oxidation state of I in `I^(-)` is -1. - In molecular iodine `I_(2)`, the oxidation state of I is 0. - The oxidation state increases from -1 to 0, indicating an oxidation process. **Conclusion**: This is an oxidation process. ### Final Conclusion: The pairs of oxidation processes are found in options (c) and (d). Therefore, the correct answer is: **Correct Options**: (c) and (d)
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