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10.78 g of H3 PO4 in 550 ml solution is ...

10.78 g of `H_3 PO_4` in 550 ml solution is 0.40 N. Thus this acid:

A

has been neutralised to `HPO_(4)^(2-)`

B

has been neautralised to `PO_(4)^(3-)`

C

has been reduced to `HPO_(3)^(2-)`

D

has been neutralised to `H_(2)PO_(4)^(-)`

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The correct Answer is:
A
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MOTION-OXIDATION & REDUCTION -EXERCISE-2 ( LEVEL-II)
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