To 25 ml of H(2)O(2) solution, excess of...

To 25 ml of `H_(2)O_(2)` solution, excess of acidified solution of KI was added. The iodine liberated required 20 ml of 0.1 N `Na_(2)S_(2)O_(3)` solution. Calculate the % of `H_(2)O_(2)` solution.

0.000136

0.00136

6.8E-5

0.00068

Text Solution

Verified by Experts

The correct Answer is:

Topper's Solved these Questions

OXIDATION & REDUCTION
MOTION|Exercise EXERCISE -3(BALANCING OF REACTIONS )|56 Videos
OXIDATION & REDUCTION
MOTION|Exercise EXERCISE -4(LEVEL-I)|14 Videos
OXIDATION & REDUCTION
MOTION|Exercise EXERCISE-2 ( LEVEL-I)|50 Videos
NOMENCLATURE OF ORGANIC COMPOUNDS
MOTION|Exercise PREVIOUS YEAR|8 Videos
P-BLOCK ELEMENTS
MOTION|Exercise Exercise - 4 | Level-I Previous Year | JEE Main|37 Videos

Similar Questions

Explore conceptually related problems

To a 25 mL of H_(2)O_(2) solution, excess of acidified solution of KI was added. The iodine liberated required 20 mL of 0.3 N Na_(2)S_(2)O_(3) solution. Calculate the volume strength of H_(2)O_2 solution. Strategy : Volume strength of H_(2)O_(2) solution is related to its normality by the following relation Volume strength (V)=5.6xx"Normality" (N) where, Normality =((meq)H_(2)O_(2))/V_(mL) According to the law of equivalence (meq)_(Na_(2)S_(2)O_(3))=(meq)_(I_(2))=(meq)_(H_(2)O_(2))

To a 25 mL H_2 O_2 solution, excess of acidified solution of KI was added. The iodine liberated required 20.0 mL of 0.3 N Na_2 S_2 O_3 solution. Calculate the volume strength of H_2 O_2 solution.

25 mL of H_(2)O_(2) solution were added to excess of acidified solution of KI . The iodine so liberated required 20 mL of 0.1N Na_(2)S_(2)O_(3) for titration Calculate the strength of H_(2)O_(2) in terms of normalility, percentage and volumes. (b) To a 25 mL H_(2)O_(2) solution, excess of acidified solution of KI was added. The iodine liberated required 20 mL of 0.3N sodium thiosulphate solution. Calculate the volume strength of H_(2)O_(2) solution.

MOTION-OXIDATION & REDUCTION -EXERCISE-2 ( LEVEL-II)

How many litres of a 0.5 N solution of an oxidising agent are reduced ...
Text Solution
|
In the titration of K(2)Cr(2)O(7) and ferrous sulphate, following data...
Text Solution
|
To 25 ml of H(2)O(2) solution, excess of acidified solution of KI was ...
Text Solution
|
10 g mixture of KI and NaClO(3) treated with 200 cc HCl gives a gas wh...
Text Solution
|
100 ml of 0.15 N H(2)O(2) is completely oxidized by
Text Solution
|
An aqueous solution of 6.3 g of oxalic acid dihydrate is made upto 250...
Text Solution
|
In the standardization of Na(2)S(2)O(3) using K(2)Cr(2)O(7) by iodomet...
Text Solution
|
A 110% sample of oleum contains
Text Solution
|
30 " mL of " a solution containing 9.15gL^(-1) of an oxalate K(x)H(y...
Text Solution
|
30 " mL of " a solution containing 9.15gL^(-1) of an oxalate K(x)H(y...
Text Solution
|
30 " mL of " a solution containing 9.15gL^(-1) of an oxalate K(x)H(y...
Text Solution
|
30 " mL of " a solution containing 9.15gL^(-1) of an oxalate K(x)H(y...
Text Solution
|
A steel sample is to be analysed for Cr and Mn simultaneously . By sui...
Text Solution
|
A steel sample is to be analysed for Cr and Mn simultaneously . By sui...
Text Solution
|
A steel sample is to be analysed for Cr and Mn simultaneously . By sui...
Text Solution
|
25 ml from a stock solution containing NaHCO(3) and Na(2)CO(3) was di...
Text Solution
|
25 ml from a stock solution containing NaHCO(3) and Na(2)CO(3) was di...
Text Solution
|
25 ml from a stock solution containing NaHCO(3) and Na(2)CO(3) was di...
Text Solution
|
1.16 g CH(3)(CH(2))(n)COOH was burnt in excess air and the resultant g...
Text Solution
|
1.16 g CH(3)(CH(2))(n)COOH was burnt in excess air and the resultant g...
Text Solution
|