Home
Class 12
CHEMISTRY
200 " mL of " a solution of a mixture of...

200 " mL of " a solution of a mixture of NaOH and `Na_2CO_3` was first titrated with 0.1 M HCl using phenolphthalein indicator. 17.5 " mL of " HCl was required for the same HCl was again required for next end point. Find the amount of NaOH and `Na_2CO_3` in the mixture.

Text Solution

Verified by Experts

The correct Answer is:
0.6 gm ; 0.0265gm
Promotional Banner

Topper's Solved these Questions

  • OXIDATION & REDUCTION

    MOTION|Exercise EXERCISE -4(LEVEL-I)|14 Videos
  • OXIDATION & REDUCTION

    MOTION|Exercise EXERCISE -4(LEVEL-II)|10 Videos
  • OXIDATION & REDUCTION

    MOTION|Exercise EXERCISE-2 ( LEVEL-II)|50 Videos
  • NOMENCLATURE OF ORGANIC COMPOUNDS

    MOTION|Exercise PREVIOUS YEAR|8 Videos
  • P-BLOCK ELEMENTS

    MOTION|Exercise Exercise - 4 | Level-I Previous Year | JEE Main|37 Videos

Similar Questions

Explore conceptually related problems

30 " mL of " a solution of mixture of Na_2CO_3 and NaHCO_3 required 12 " mL of " 0.05 M H_2SO_4 using phenolphthalein as indicator. With methyl orange 30 " mL of " the same solution required 40 " mL of " same H_2SO_4 . Calculate the amount of Na_2CO_3 and NaHCO_3 per litre in the mnixture.

A mixture NaOH+Na_(2)CO_(3) required 25mL of 0.1 M HCl using phenolpththalein as the indicator. However, the same amount of the mixture required 30mL of 0.1M HCl when methyl orange was used as the indicator. The molar ration of NaOH and Na_(2)CO_(3) in the mixture was:

0.4 g mixture of NaOH, Na_2CO_3 , and some inert N impurities was first titrated with N/(10) HCl using phenolphthalein as an indicator, 17.5 ml. of HCI was required at the end point. After this methyl orange was added and titrated. 1.5 mL of same HCl was required for the next end point. The weight percentage of Na_2CO_3 , in the mixture is (Rounded-off to the nearest integer)

3.65gm equimole mixture of NaOH and Na_(2)CO_(3) is titrated against 0.1M HCl using phenolphathalein as an indicator, V_(1)mL of acid was required to reach end point. In another experiment 3.65gm of same mixture is titrated against 0.2M HCl using methyl orange as an indicator, V_(2)mL of acid was required to reach end point. V_(1)+V_(2) is :

MOTION-OXIDATION & REDUCTION -EXERCISE -3(BALANCING OF REACTIONS )
  1. A solution contains Na(2)CO(3) and NaHCO(3) . 20 ml of this solution r...

    Text Solution

    |

  2. A solution contains a mixture of Na(2)CO(3) and NaOH. Using Ph as indi...

    Text Solution

    |

  3. 200 " mL of " a solution of a mixture of NaOH and Na2CO3 was first tit...

    Text Solution

    |

  4. It requires 40mL of 1 M Ce^(4+) to titrate 20mL of 1 M Sn^(2+) " to "S...

    Text Solution

    |

  5. A volume of 12.53 ml of 0.05093 M SeO(2) reacted with exactly 25.52 ml...

    Text Solution

    |

  6. Potassium acid oxalate K(2)C(2)O(4). 3H(2)C(2)O(4). 4H(2)O can be oxi...

    Text Solution

    |

  7. A 1 g sample of H(2)O(2) solution containing x% H(2)O(2) by mass requi...

    Text Solution

    |

  8. Metallic tin in the presence of HCl is oxidized by K(2)Cr(2)O(7) to st...

    Text Solution

    |

  9. 5g sample of brass was dissolved in one litre dil. H(2)SO(4) . 20 ml o...

    Text Solution

    |

  10. A 1.0 g sample of Fe(2)o(3) solid of 55.2 % purity is dissolved in aci...

    Text Solution

    |

  11. 0.84 g iron ore containing x percent of iron was taken in a solution c...

    Text Solution

    |

  12. 8.7gm of pyrolusite (impure MmO(2)) were heated with concentrated HCl...

    Text Solution

    |

  13. 50 gm of a sample of Ca(OH)(2) is dissolved in 50 ml of 0.5 N HCl solu...

    Text Solution

    |

  14. One gm of impure sodium carbonate is dissolved in water and the soluti...

    Text Solution

    |

  15. What amount of substance containing 60% NaCl, 37% KCl should be weighe...

    Text Solution

    |

  16. 10 g CaCO(3) were dissolved in 250 ml of 1 M HCl. What volume of 2 M K...

    Text Solution

    |

  17. A mixture of FeO and Fe(2)O(3) is reacted with acidified KMnO(4) solut...

    Text Solution

    |

  18. 50 ml of a solution, containing 0.01 mole each Na(2)CO(3),NaHCO(3) and...

    Text Solution

    |

  19. 50 ml of a solution, containing 0.01 mole each Na(2)CO(3),NaHCO(3) and...

    Text Solution

    |

  20. 50 ml of a solution, containing 0.01 mole each Na(2)CO(3),NaHCO(3) and...

    Text Solution

    |