What amount of substance containing 60% NaCl, 37% KCl should be weighed out for analysis so that after the action of 25 ml of 0.1N `AgNO_(3)` solution, excess of `Ag^(+)` is back titrated with 5 ml of `NH_(3)SCN` solution? Given that 1 ml of `NH_(4)SCN` = 1.1 ml of `AgNO_(3)`.
`[AgNO_(3)+NaSCN rarr AgSCN + NaNO_(3) ]`

Answer

0.1281g