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5.7 g of bleaching powder was suspended ...

`5.7 g` of bleaching powder was suspended in `500 mL` of water. `25 mL` of this suspension on treatment with `KI` and `HCl` liberated iodine which reacted with `24.35 mL "of" N//10Na_(2)S_(2)O_(3)`. Calculate `%` of available `Cl_(2)` in bleaching powder.

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The correct Answer is:
0.3033
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0.71 g of a sample of bleaching powder (CaOCl_2) is dissolved in 100 " mL of " water. 50 " mL of " this solution is titrated with KI solution. The I_2 so liberated required 10 mL 0.1 M Na_2S_2O_3 (hypo) solution in acidic medium for complete neutralisation. Calculate the percentage of available Cl_2 from the sample of bleaching power.

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