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Calculate work for the expansion of a su...

Calculate work for the expansion of a subsatnce from `3m^(3)` to `5m^(3)` against.
Constant pressure `=10^(5)Pa`

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Verified by Experts

(a) `W=-PdV=-10^(5)(5-3)=-2xx10^(5)J`
(B) `W=-int(10+5V)dV`
= `-(10V+(5V^(2))/2)^(5)=-[(10xx2)+5/2xx16]`
= -(20 + 40) = -60
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