" (iii) "[3x-5y+1=0],[6x-y+3=0]

Solve : 3x- 5y + 1=0 2x - y + 3=0

Solve the following pair of linear equations by the substitution method. (i) x+y=14 ;x- y=4 (ii) s-t=3; s/3+t/2=6 (iii) 3x-y=3;9x-3y=9 (iv) 0. 2 x+0. 3 y=1. 3 ;0. 4 x+0. 5 y=2. 3 (v) sqrt(2)x+sqrt(3)y=0;sqrt(3)x-sqrt(8)y=0 (vi) 3x/2-5y/2=-2;x/3+y/2=13/6

Solve the following pair of linear equations by the substitution method. (i) x+y=14 ;x- y=4 (ii) s-t=3; s/3+t/2=6 (iii) 3x-y=3;9x-3y=9 (iv) 0. 2 x+0. 3 y=1. 3 ;0. 4 x+0. 5 y=2. 3 (v) sqrt(2)x+sqrt(3)y=0;sqrt(3)x-sqrt(8)y=0 (vi)3x/2-5y/2=-2;x/3+y/2=13/6

6x-3y=-10,3x+5y-8=0

Prove that the following lines are concurrent. (i)5x-3y=1 , 2x+3y=23 , 42x+21y=257 (ii) 2x+3y-4=0 , x-5y+7=0 , 6x-17y+24=0

Solve by cross-multiplication method. (i) 8x-3y=12,5x=2y +7 (ii) 6x+ 7y -11 =0, 5x+ 2y =13 (iii) (2)/(x)+(3)/(y) =5, (3)/(x) -(1)/(y) +9=0

Find the solution of 3x-5y+1=0,-7x+3y+15=0

Equation of the line equidistant from 3x+4y-25=0 and 3x+4y+25=0 is (A) 6x+4y+5=0 (B) 3x+4y=0 (C) 3x-4y+5=0 (D) 6x+8y+5=0

Equation of the line equidistant from 3x+4y-25=0 and 3x+4y+25=0 is (A) 6x+4y+5=0 (B) 3x+4y=0 (C) 3x-4y+5=0 (D) 6x+8y+5=0