" 31.If "f(x)={[(2^(x+2)-16)/(4^(x)-16),," if "x!=2],[k,," if "x=2]" is continuous at "x=2," find "k

f(x)={(2^(x+2)-16)/(4^(x)-16),quad if x!=2k,quad if x=2 is continuous at x=2, find k

find the value of k, so that the function f(x)={((2^(x+2)-16)/(4^(x)-16)", if "x!=2),(k", if "x=2):} is continuous at x=2.

f(x)={(2^(x+2)-16)/(4^(x)-16),quad if x!=2 and k, if x=2 at x=2

f(x)= {((2^(x + 2)-16)/(4^(x)-16)",",x ne 2),(k",",x=2):} f(x) is continuous at x=2 then find k

If f(x)={(2^(x+2)-16)/(4^x-16),if x!=2k ,if f(x) is continuous a t x=2, find k

If f(x)={((2^(x+2)-16)/(4^x-16),x!=2),(k, x=2):} is continuous at x=2 , find k .

If the function f(x)=(2^(x+2)-16)/(4^(x)-16) for x!=2;-A for x=2 is continuous at x=2 then A

Find the value of 'k', such that the function : f(x) = {:{(2x^(x+2)-16)/(4^x -16), if x ne2),(k, if x =2):} is continuous at x =2

If f(x) ={{:((2^(x+2)-16)/(4^(x)-16), if x ne 2 ),(k, if x = 2):} , is 'conti nuous' at x = 2 . then find 'k'.

Find the value of k so that the function f(x) = {((2^(x+2) - 16)/(4^(x) - 16),"if",x ne 2),(" k","if",x = 2):} is continuous at x = 2.