Calculate the free energy change at 298 K for the reaction , `Br_(2)(l)+Cl_(2)(g)to2BrCl(g)`. For the reaction `DeltaH^(@)=29.3kJ` & the entropies of `Br_(2)(l),Cl_(2)(g)&BrCl(g)` at the 298 K are 152.3, 223.0, 239.7 J`mol^(-1)K^(-1)` respectively.

Explanation

To calculate the free energy change (ΔG) at 298 K for the reaction:

\[ \text{Br}_2(l) + \text{Cl}_2(g) \rightarrow 2 \text{BrCl}(g) \]

we will follow these steps:

### Step 1: Write down the given values
- ΔH° = 29.3 kJ = 29.3 × 10³ J (convert to Joules for consistency)
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