Solve the initial value problem `y^(prime)=ycot2x ,y(pi/4)=2.`

Explanation

Given:

`y^(prime)=ycot2x`

`(dy)/(dx)=ycot2x`

`int(dy)/y=int(cos2x)/(sin2x)`

`implieslog∣y∣=1/2log∣sin2x∣+log∣C_1∣`

Therefore,

`|y/(sqrt(sin2x))|=C_1`

`y/(sqrt(sin2x))=+-C_1=C.....(i)`

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