sqrt(x-(3)/(4))," where "x>=34

Solve the equation x^(2)-x+1=(1)/(2)+sqrt(x-(3)/(4)), where x>=(3)/(4)

sqrt((-x)/(4)) + sqrt((-x)/(16))- sqrt((-x)/(64)) , where x is a positive real number

If x= sqrt(-sqrt3+ sqrt(3+8 sqrt(7+4 sqrt3))) where x>0, then the value of x is equal to: यदि x= sqrt(-sqrt3+ sqrt(3+8 sqrt(7+4 sqrt3))) तो x का मान ज्ञात करे: जहा x>0

Solve dy/dx+y/sqrt(x^2+4)=3x where y(0)=4

if f(x)=sqrt(xg)(x) where g(4)=2 and g(4)=3,findf(4)

P=(124-32sqrt(15))^((1)/(4)),q=(x^(4)+(1)/(x^(4))) where x=sqrt(3+2sqrt(2)), then ((q-p^(2))/(sqrt(15))) is

(sqrt(x)+sqrt(y))^(2)=x+y+2sqrt(xy) and sqrt(x)sqrt(y)=sqrt(xy) , where x and y are positive real numbers . If x=2sqrt(5)+sqrt(3) and y=2sqrt(5)-sqrt(3) , then x^(4)+y^(4) =

The function f(x)=(x-3)^(2) satisfies all the condition of mean value theorem in [3,4].A point on y=(x-3)^(2), where the tangent is parallel to the chord joining (3,0) and (4.1) is

Find the domain of f(x)=sqrt(([x]-1))+sqrt((4-[x])) (where [ ] represents the greatest integer function).