For a certain curve y=f(x) satisfying
`(d^(2)y)/(dx^(2))=6x-4,` f(x) has a local minimum value 5 when x=1, Find the equation of the curve and also the gobal maximum and global minimum values of f(x) given that `0lexle2.`

For a certain curve y=f(x) satisfying (d^(2)y)/(dx^(2))=6x-4,f(x) has a local minimum value 5 when x=1 . The global maximum value of f(x) if 0lexle2 , is

For certain curve y=f(x) satisfying (d^(2)y)/(dx^(2))=6x-4, f(x) has local minimum value 5 when x=1 Global maximum value of y=f(x) for x in [0,2] is

The curve y =f (x) satisfies (d^(2) y)/(dx ^(2))=6x-4 and f (x) has a local minimum vlaue 5 when x=1. Then f^(prime)(0) is equal to :

A curve y=f(x) satisfies (d^2y)/dx^2=6x-4 and f(x) has local minimum value 5 at x=1 . If a and b be the global maximum and global minimum values of f(x) in interval [0,2] , then ab is equal to…

Find the local maximum and local minimum value of f(x)= x^(3)-3x^(2)-24x+5

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Find the local maximum and local minimum values of f(x)=sec x+log cos^(2)x,quad 0

For certain curves y= f(x) satisfying [d^2y]/[dx^2]= 6x-4, f(x) has local minimum value 5 when x=1. 9. Number of critical point for y=f(x) for x € [0,2] (a) 0 (b)1. c).2 d) 3 10. Global minimum value y = f(x) for x € [0,2] is (a)5 (b)7 (c)8 d) 9 11 Global maximum value of y = f(x) for x € [0,2] is (a) 5 (b) 7 (c) 8 (d) 9

For a certain curve (d ^(2)y)/(dx ^(2))=6x -4 and curve has local minimum values 5 at x=1, Let the global maximum and global minimum vlaues, where 0 le x le 2, are M and m. Then the vlaue of (M-m) equals to :