A mercury drop of radius 1 cm is sprayed into `10^(6)` dropletes of equal size. Calculates the energy expanded if surface tension of mercury is `35 xx 10^(-3) N//m`.

Explanation

To solve the problem of calculating the energy expanded when a mercury drop of radius 1 cm is sprayed into \(10^6\) droplets of equal size, we can follow these steps:

### Step 1: Understand the conservation of volume
The volume of the larger mercury drop must equal the total volume of the smaller droplets.

**Volume of the larger drop (V_large)**:
\[
V_{\text{large}} = \frac{4}{3} \pi R^3
...