Home
Class 12
PHYSICS
Velocity of water in a river is...

Velocity of water in a river is

Text Solution

Verified by Experts

As velocity at the bottom of the river will be zero, velocity gradient,
`( dv)/( dy ) = ( 18 xx 10^(3))/( 60 xx 60 xx 15 ) = 1 s^(-1)`
Now as the viscous force `F = eta A ( dv //dy)` is tangential to the area, Shear stress `= ( F_(11))/( A) = eta( dv)/( dy)`
`= 10^(-3) xx 1 = 1 xx 10^(-3) N//m^(2)`
Promotional Banner

Topper's Solved these Questions

  • SURFACE TENSION & VISCOSITY

    MOTION|Exercise Exercise - 1 Objective Problems | JEE Main|19 Videos
  • SURFACE TENSION & VISCOSITY

    MOTION|Exercise Exercise - 2 (Level-I) Objective Problems | JEE Main|11 Videos
  • SURFACE TENSION

    MOTION|Exercise Exercise - 3 | Section - B Previous Year Problems | AIEEE|12 Videos
  • Thermodynamics

    MOTION|Exercise EXERCISE - 3 SECTION b|26 Videos

Similar Questions

Explore conceptually related problems

Give reason for the following: (a) Machine parts get jammed in the winters. (b) A constant driving force is always required for the maintenance of the flow of oil through pipe lines in the refineries. (c) Velocity of water in a river is less near the banks and more in the middle.

The velocity of water in river is 9 km/h of the upper surface . The river is 10 m deep . If the coefficient of viscosity of water is 10^(-2) poise then the shearing stress between horizontal layers of water is

The velocity of water in river is 180 km h^(-1) near the surface .If the river is 5 m deep,then the shearing stress between the surface layer and the bottom layer is ( cofficient of viscosity of water eta =10^(-3) Pa s)

The velocity of water near a river's surface is 20 km/hr. If the depth of the river is 4 m, calculate the shearing stress between the horizontal layers of water. Take, coefficient of viscosity of water = 0.01 poise.

A person reaches on a point directly opposite on the other bank of a river.The velocity of the water in the river is 4 m//s and the velocity of the person in still water is 5 m//s .If the width of the river is 84.6m , time taken to cross the river in seconds is

Velocity of man w.r.t river is equal to velocity at river value of theta for which man reaches directly at B

A swimmer crosses the river along the line making an angle of 45^(@) with the direction of flow. Velocity of the river is 5 m/s. Swimmer takes 6 seconds to cross the river of width 60 m. The velocity of the swimmer with respect to water will be :

A swimmer crosses the river along the line making an angle of 45^@ with the direction of flow. Velocity of the river water is 5(m)/(s) . Swimmer takes 12 seconds to cross the river of width 60 m. The velocity of the swimmer with respect to water will be:

We know that when a boat travels in water, its net velocity w.r.t. ground is the vector sum of two velocities. First is the velocity of boat itself in river and other is the velocity of water w.r.t. ground. Mathematically: vecv_(boat) = vecv_(boat,water) + vecv_(water) . Now given that velocity of water w.r.t. ground in a river is u. Width of the river is d. A boat starting from rest aims perpendicular to the river with an acceleration of a = 5t, where t is time. The boat starts from point (1,0) of the coordinate system as shown in figure. Assume SI units.