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Calculate the work done against surface tension in blowing a soap bubble from a radius of `10 cm` to `20 cm`, if the surface tension of soap solution is `25xx10^(-3)N//m`.

Answer

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Calculate the work down against surface tension in blowing a soap bubble from a radius of 10 cm to 20 cm , if the surface tension of soap solution in 25xx10^(-3)N//m .

Calculate the work done agains surface tension in blowing a soap bubble from a radius 10 cm to 20 cm if the surface tension of soap solution is 25xx10^(-3)N//m then compare it with liquid drop of same radius.

Knowledge Check

  • The work done in blowing a soap bubble from a radius of 6 cm to 9 cm if surface tension of soap solution is 25xx10^(-3) N//m , is

    A
    `90pixx10^(-5)`J
    B
    `60 pixx10^(-5)`
    C
    `60pixx10^(-5)`
    D
    `90pixx10^(-6)` J

  • What will be the work done in blowing a soap bubble of radius 1 cm to 2 cm ? (If surface tension of soap solution is 25 xx 10^(-3) N/m)

    A
    `6 pi xx 10^(5)` J
    B
    ` 6 pi xx 10^(6)` J
    C
    ` 24 pi xx 10^(-5)` J
    D
    ` 20 xx 10^(6)` J

  • The work done in blowing a soap bubble of radius 0.2 m is (the surface tension of soap solution being 0.06 N/m )

    A
    `192 pi xx10^(-4) J`
    B
    `280pixx10^(-4) j`
    C
    `200 pixx10^(-3)` j
    D
    None of these

    • Similar Questions

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    Calculate the work done in blowing a soap bubble from a radius of 2cm "to" 3cm. The surface tension of the soap solution is 30" ""dyne"" "cm^(-2).

    What will be the work done in blowing out a soap bubble of radius 0.4 cm? The surface tension of soap solution is 30 xx 10^(-3)" N/m".

    What will be the work done in blowing a soap bubble from a radius of 3 cm to a radius of 5 cm? The surface tension of soap solution is 40 dyne cm ""^(-1) .

    Work done in increasing the size of a soap bubble from a radius of 3 cm to 5 cm is nearly. (surface tension of soap solution = 0.3 Nm^(-1))

    The work done in blowing a soap bubble of radius 5 cm is

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