Several spherical drops of a liquid each of radius r coalesce to form a single drop of radius R. If T is the surface tension, then the energy liberated will be -

Several spherical deops of a liquid each of radius r coalesece to from a single drop of radius R. If T is the surface tension, then the energy liberated will be

Several spherical drops of a liquid of radius r coalesce to form a single drop of radius R . If T is surface tension and V is volume under consideration, then the release of energy is

A certain number of spherical drops of a liquid of radius r coalesce to form a single drop of radius R and volume V . If T is the surface tension of the liquid, then

A number of droplets, each of radius r , combine to form a drop of radius R . If T is the surface tension, the rise in temperature will be

Some drops each of radius r coalesce to form a large drop of radius R . The surface tension T. Find the change in surface energy per unit volume?

n droplets of equal size and each of radius r coalesce to form a bigger drop of radius R. the energy liberated is equal to

n number of water droplets, each of radius r , coalese, to form a single drop of radius R . The rise in temperature d theta is

A liquid drop of radius R is broken into 1000 drops each of radius r. If T is surface tension, change in surface energy is

n small droplets of water, each of radius r, coalesce ot form a single drop of radius R. Find (i) Velocity acquired by bigger drop if all the energy released is converted into kinetic energy. (ii) Rise in temperature. Take, surface tension of water =sigma Mechanical equivalent of heat =Q

If a number of little droplets of water, each of radius r , coalesce to form a single drop of radius R , show that the rise in temperature will be given by (3T)/J(1/r-1/R) where T is the surface tension of water and J is the mechanical equivalent of heat.