Home
Class 12
PHYSICS
In displacement method, the distance bet...

In displacement method, the distance between object and screen is 96cm. The ratio of lengths of two images formed by a converging lens placed between them is 4. Then,

A

Ratio of the length of object to the length of shorter image is 2.

B

Distance between the two positions of the lens is 32 cm.

C

Focal length of the lens is `64/3` cm.

D

When the shorter image is formed on screen, distance of the lens from the screen is 32 cm.

Text Solution

Verified by Experts

The correct Answer is:
A, B, C, D
Promotional Banner

Topper's Solved these Questions

  • GEOMETRICAL OPTICS

    MOTION|Exercise Exercise - 2 (Level-II) Section M - Chromatic Aberration and Achromatism, Optical Instrument + Eye + Luminous Intensity|2 Videos
  • GEOMETRICAL OPTICS

    MOTION|Exercise Exercise - 3 | Level-I (Section A - Plane Mirror)|10 Videos
  • GEOMETRICAL OPTICS

    MOTION|Exercise Exercise - 2 (Level-II) Section K - Lens Maker formula and Magnification, Image formation by convex and concave lens, Combination of lens, Cutting of lens|3 Videos
  • FLUID

    MOTION|Exercise Exercise-4 level-II|5 Videos
  • GRAVITATION

    MOTION|Exercise Exercise - 4 Section - B Previous Years Problems|15 Videos

Similar Questions

Explore conceptually related problems

In displacement method, the distance between object and screen is 96 cm. The ratio of length of two images formed by a convex lens placed between them is 4.84.

In a displacement method the distance between the object and the screen is 70 cm and the focal length of the lens is 16 cm, find the separations of the magnified and diminished image position of the lens.

In the displacement method the distance between the object and the screen is 70 cm and the focal length of the lens is 16 cm, find the seperation of the magnified and diminished image position of the lens.

The minimum distance between a real object and its real image formed by a thin converging lens of focal length f is

In the displacement method , a convex lens is placed in between an object and a screen . If one of them magnification is 3 and the displacement of the lens between the two positions is 24 cm , then the focal length of the lens is :-

In displacement method distance of object and screen is 100 cm initial image is obtained on screen. Now lens is displaced 40 cm image formed on screen again . If power of the lens is (100/N) dioptre, then find the value of N :

The distance between an object and the screen is 100cm. A lens produces an image on the screen when the lens is placed at either of the positions 40cm apart. The power of the lens is nearly