The period of oscillation of a freely suspended bar magnet is 4 second. If it is cut into two equal parts length wise then the time period of each part will be

Options

A. 4 sec
B. 2 sec
C. 0.5 sec
D. 0.25 sec

Explanation

To solve the problem, we need to determine the time period of oscillation of each half of a bar magnet after it has been cut in half lengthwise.

### Step-by-Step Solution:

1. **Understand the Initial Conditions:**
- The time period of the original bar magnet is given as \( T = 4 \) seconds.

2. **Identify the Formula for Time Period:**
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