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A square frame of side l carries a curre...

A square frame of side `l` carries a current produces a field `B` at its centre. The same current is passed through a circular loop having same perimeter as the square. The field at its centre is `B'`, the ratio of `B//B'` is

Text Solution

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`(8sqrt2)/(pi^(2))`
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A current I produces a magnetic field B at the centre of the circular coil. If the coil rewound to double its number of turns then what is the magnetic field at its centre in terms of B?

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Knowledge Check

  • A square frame of side 1 m carries a current I, produces a magnetic field B at its centre. The same current is passed through a circular coil having the same perimeter as the square. The magnetic field at the centre of the circular coil is B'. The ratio B"/"B is

    A
    `(8)/(pi^(2))`
    B
    `(8sqrt2)/(pi^(2))`
    C
    `(16)/(pi^(2))`
    D
    `(16sqrt2)/(pi^(2))`

  • A square loop of side a carris a current I . The magnetic field at the centre of the loop is

    A
    `(2mu_0Isqrt2)/(pia)`
    B
    `(mu_0Isqrt2)/(pia)`
    C
    `(4mu_0Isqrt2)/(pia)`
    D
    `(mu_0I)/(pia)`

  • A square loop of edge 'a' carries a current l. The magnetic field at the centre of loop is

    A
    `(mu_(0)l)/(2 sqrt2 pi a)`
    B
    `(2sqrt2 mu_(0)l)/(pi a)`
    C
    `(mu_(0)l)/(sqrt2pi a)`
    D
    `(mu_(0)lsqrt2)/(pi a)`

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