Home
Class 12
PHYSICS
Show that if the flux of magnetic induct...

Show that if the flux of magnetic induction through a coil changes from `phi_(1)" to "phi_(2)` then the charge q that flows through the circuit of total resistance R is given by `q=(phi_(2)-phi_(1))/(R)` where R is the resistance of the coil.

Text Solution

Verified by Experts

Let `phi` be the instantaneous flux. Then `(dphi)/(dt)` is the instantaneous rate of change of flux which is equal to the magnitude of the instantaneous emf. So the current in the circuit `|i|=(1)/(R)((dphi)/(dt))` , since the current is the rate of flow of charge, that is, `i=(dq)/(dt)`
`q=intidtorq=underset(t=0)overset(t=t)int((1)/(R).(dphi)/(dt))dt`
where `tau` is the time during which change takes place. but at `t=0, phi=phi_(1),` and at `t=t,phi=phi_(2)`
`:. `:.q=(1)/(R)underset(phi=phi_(1))overset(phi=phi_(2))intdphi=(phi_(2)-phi_(1))/(R)`
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • ELECTROMAGNETIC INDUCTION

    MOTION|Exercise EXERCISE-1|25 Videos

  • ELECTROMAGNETIC INDUCTION

    MOTION|Exercise EXERCISE-2 (LEVEL-I)|16 Videos

  • ELECTRO MAGNETIC WAVES

    MOTION|Exercise EXERCISE - 3 (SECTION - B)|8 Videos

  • ELECTROMAGNETISM

    MOTION|Exercise Exercise|136 Videos

Similar Questions

Explore conceptually related problems

The magnetic flux linked with a coil of N turns and resistance R changes from phi_(1) " to " phi_(2) . Show that the charge that has passed through the coil is q=-(N(phi_(2)-phi_(1)))/( R) .

The total electric flux phi through the entire area of a closed surface is given by

Knowledge Check

  • The charge flowing through a resistance R varies with time t as Q=at-bt^(2) , where a and b are positive constant. The total heat produced in R is

    A
    `(a^(3)R)/(2b)`
    B
    `(a^(3)R)/(b)`
    C
    `(a^(3)R)/(6b)`
    D
    `(a^(3)R)/(3b)`

  • A time varying magnetic flux passing through a coil is given by phi=xt^(2) , if at t=3s , the emf induced is 9 V, then the value of x is

    A
    `0.66Wb//s^(2)`
    B
    `-0.66Wb//s^(2)`
    C
    `1.5Wb//s^(2)`
    D
    `-1.5Wb//s^(2)`

  • The charge flowing through a resistance R varies with time t as Q = at - bt^(2) . The total heat produced in R is

    A
    `(a^(3) R)/(6 b)`
    B
    `(a^(3) R)/(3 b)`
    C
    `(a^(3) R)/(2 b)`
    D
    `(a^(3) R)/( b)`

    • Similar Questions

    Explore conceptually related problems

    There lis a coil of resistance R. Calculate amount of charge that flows through the coil if associated fluc is increased from phi_(1) to phi_(2) .

    A frustum is cut from a right circular cone. The two circular faces have radii R and 2R and their centers are at O_(1) and O_(2) respectively. Height of the frustum is h=3R . When a point charge Q is placed at O_(1) , the flux of electric field through the circular face of radius 2R is phi_(1) and when the charge Q is placed at O_(2) , the flux through the other circular face is phi_(2) . find the ratio (ph_(1))/(phi_(2))

    If the electric flux entering and leaving an enclosed surface are phi_1 and phi_2 respectively, then the electric charge present within the surface is

    The charge flowing through a resistance R varies with time t as Q=at - bt^(2) , where a and b positive constants. The total heat produced in R is :

    The charge flowing through a resistance R varies with time t as Q=at - bt^(2) , where a and b positive constants. The total heat produced in R is :

    Home
    Profile