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A metallic rod length L and the mass M i...

A metallic rod length `L` and the mass `M` is moving under the action of two unequal `F_(1)` and `F_(2)` (directed opposite to each other) acting at its ends along its length. Ignore gravity and any external magnetic field. If sepecific charge of electrons is `(e//m)`, then the potential difference between the ends of the rod is steady state must be

A

`|F_(1)-F_(2)|mL//eM`

B

`(F_(1)-F_(2))mL//eM`

C

`[mL//eM] ln[F_(1)//F_(2)]`

D

None

Text Solution

Verified by Experts

The correct Answer is:
A
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