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A proton moves with a speed of 7.45xx10^...

A proton moves with a speed of `7.45xx10^(5) m//s` dirctly towards a free proton originally at rest. Find the distance of closest approach for the two protons.
Given : `(1)/(4pi in_(0))=9xx10^(9)(N-m^(2))/C^(2), m_(p)=1.67xx10^(-27) kg` and `e=1.6xx10^(-19) C`

A

`10^(-12)m`

B

`10^(-14)m`

C

`10^(-10)`m

D

`10^(-8)m`

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The correct Answer is:
A
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MOTION-ELECTROSTATICS-Exercise -1 (Objective Problems | NEET)
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