If three electric di-poles are placed in some closed surface, then the electric flux emitting from the surface will be -

Options

A. zero
B. positive
C. negative
D. None

Answer

To solve the problem of determining the electric flux emitting from a closed surface containing three electric dipoles, we can follow these steps:

### Step-by-Step Solution:

1. **Understanding Electric Dipoles**:
An electric dipole consists of two equal and opposite charges separated by a distance. For example, if we have a dipole with charges +q and -q, the net charge of the dipole is zero.

2. **Identifying the Closed Surface**:
We are given that three electric dipoles are placed within a closed surface. This closed surface can be treated as a Gaussian surface for the application of Gauss's law.

3. **Applying Gauss's Law**:
Gauss's law states that the electric flux (Φ) through a closed surface is equal to the total charge (Q) enclosed by that surface divided by the permittivity of free space (ε₀):
\[ \Phi = \frac{Q_{\text{enclosed}}}{\varepsilon_0} \]

4. **Calculating the Enclosed Charge**:
Since each dipole consists of a positive and a negative charge, the net charge of each dipole is zero. Therefore, for three dipoles:
- Dipole 1: +q and -q → Net charge = 0
- Dipole 2: +q and -q → Net charge = 0
- Dipole 3: +q and -q → Net charge = 0
Thus, the total charge enclosed by the closed surface is:
\[ Q_{\text{enclosed}} = 0 + 0 + 0 = 0 \]

5. **Finding the Electric Flux**:
Substituting the enclosed charge into Gauss's law:
\[ \Phi = \frac{0}{\varepsilon_0} = 0 \]

6. **Conclusion**:
The electric flux emitting from the closed surface containing the three dipoles is zero.

### Final Answer:
The electric flux emitting from the surface will be **0**.

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