A surface enclosed an electric dipole, the flux through the surface is -

Options

A. Infinite
B. Positive
C. Negative
D. Zero

Answer

To find the electric flux through a surface enclosing an electric dipole, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Electric Dipole**: An electric dipole consists of two equal and opposite charges, +q and -q, separated by a distance (let's say 2d).

2. **Identify the Gaussian Surface**: We consider a closed surface (Gaussian surface) that encloses the electric dipole.

3. **Apply Gauss's Law**: According to Gauss's law, the electric flux (Φ) through a closed surface is given by:
\[ \Phi = \oint \mathbf{E} \cdot d\mathbf{A} = \frac{Q_{\text{enclosed}}}{\epsilon_0} \]
where \(Q_{\text{enclosed}}\) is the total charge enclosed by the surface, and \(\epsilon_0\) is the permittivity of free space.

4. **Calculate the Enclosed Charge**: In the case of an electric dipole, the total charge enclosed by the surface is:
\[ Q_{\text{enclosed}} = +q + (-q) = 0 \]

5. **Determine the Electric Flux**: Since the total enclosed charge is zero, we can substitute this into Gauss's law:
\[ \Phi = \frac{0}{\epsilon_0} = 0 \]

6. **Conclusion**: Therefore, the electric flux through the surface enclosing the electric dipole is zero.

### Final Answer:
The flux through the surface enclosing an electric dipole is **0**.

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