Calculate the earth's potential. Assume ...

Calculate the earth's potential. Assume earth has a surface charge density of 1` "ectron/metre"^(2)`.(Given,the electronic charge = `-1.6xx10^(-19)C," earth's radius "=6.4 xx10^(6)m,e_(0) = 8.9xx10^(-12)c^(2)//Nm^(2)`)

`+ 0.12` volt

`-0.12` volt

`-1.2 ` volt

`-1.2` volt

Text Solution

Verified by Experts

The correct Answer is:

Topper's Solved these Questions

ELECTROSTATICS
MOTION|Exercise Exercise - 2 (Objective Problems | NEET)|64 Videos
ELECTROSTATICS
MOTION|Exercise Exercise -3 Section (A)|41 Videos
ELECTROSTATICS
MOTION|Exercise SELF PRACTICE PROBLEM|27 Videos
ELECTRONICS - SEMI CONDUCTOR
MOTION|Exercise EXERCISE - 3|29 Videos
ELECTROSTATICS - I
MOTION|Exercise EXERCISE - 4 (Level -II) PREVIOUS YEAR - JEE ADVANCED|13 Videos

Similar Questions

Explore conceptually related problems

Suppose that earth has a surface charge density of 1 electron / "metre" ^(2) . Calculate earth s potential and electric field just outside earth surface . Radius of earth 6400 km.

The Avogadro's number is 6xx10^(23) per gm mole and electronic charge is 1.6xx10^(-19)C . The Faraday's number is

Find the escape velocity of a body from the earth. [M (earth ) = 6 xx 10^(24) kg, R ( earth) = 6.4 xx 10^(6) m. G = 6.67 xx 10^(-11) N.m^(2)//kg^(2)]

Find the gravitational potential energy of a body of mass 10 kg when it is on the earth's surface. [M(earth) =6xx10^(24)kg,"R (earth)"=6.4xx10^(6)m, G=6.67xx10^(-11)N.m^(2)//kg^(2)]

Calculate the electric potential energy of an electron-proton system of an atom . The radius of the orbit of the electron is 21.16xx10^(-11) m the charge on electron is 1.6xx10^(-19)C .

The charge on the electron is 1.6 xx 10^(-19) C . The order of magnitude is

A rocket is fired vertically with a speed of 5 kms^(-1) from the earth's surface. How far from the earth does the rocket go before returning to the earth ? Mass of earth= 6.0xx10^(24) kg, mean radius of the earth = 6.4xx10^(6) m, G= 6.67xx10^(-11)Nm^(2)Kg^(-2).

Calculate the mass and density of the earth. Given that Gravitational constant G = 6.67 xx 10^(-11) Nm^(2)// kg^(2) , the radius of the earth = 6.37 xx 10^(6) m and g = 9.8 m//s^(2) .

MOTION-ELECTROSTATICS-Exercise -1 (Objective Problems | NEET)

A cylinder of radius R and length l is placed in a uniform electric fi...
Text Solution
|
A surface enclosed an electric dipole, the flux through the surface is...
Text Solution
|
A square of side 20cm. Is enclosed by a surface of sphere of 80 cm. ra...
Text Solution
|
A charge q is located at the centre of a cube. The electric flux throu...
Text Solution
|
The volume charge density as a function of distance X from one face in...
Text Solution
|
A hollow sphere of charge does not produce an electric field at any-
Text Solution
|
Calculate the earth's potential. Assume earth has a surface charge den...
Text Solution
|
The electric field inside a spherical shell of uniform surface charge ...
Text Solution
|
A hollow metal sphere of radius 5 cm is charged so that the potential ...
Text Solution
|
A charged spherical conductor of radius R carries a charge Q. a point ...
Text Solution
|
The electric field intensity at a point located at distance r(r lt R) ...
Text Solution
|
The dependence of electric potential V on the distance 'r' from the ce...
Text Solution
|
Potential difference beween centre and surface of the sphere of radius...
Text Solution
|
A solid sphere of radius R has charge q uniformly distributed over its...
Text Solution
|
Two similar very small conducting spheres having vharges 40 muC and -2...
Text Solution
|
Three concentric conducting spherical shells carry charges as : +4Q on...
Text Solution
|
A solid metallic sphere has a charge +3Q. Concentric with this sphere ...
Text Solution
|
Shown in the figure a spherical shell with an inner radius 'a' and an ...
Text Solution
|
In the previous question assume that the electrostatic potential is ze...
Text Solution
|
A positive charge q is placed in a spherical cavity made in a positive...
Text Solution
|