Home
Class 12
PHYSICS
If a bullet of mass 5gm moving with velo...

If a bullet of mass 5gm moving with velocity `100m/sec, penertates the wooden block upto 6cm. Then the average force imposed by the bullet on the block is

A

417 N

B

8333N

C

83.3N

D

Zero

Text Solution

Verified by Experts

The correct Answer is:
A
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • NEWTON'S LAWS OF MOTION & FRICTION

    MOTION|Exercise Exercise - 1 (SECTION-A:- String Constrained, Wedge Constrained, Newtons Law theory Question, Equillibrium Questions (Normal and Tension), Problems with Acceleration (F=ma), Wedge problems)|27 Videos

  • NEWTON'S LAWS OF MOTION & FRICTION

    MOTION|Exercise Exercise - 1 SECTION-B :- Pulley Block System|12 Videos

  • NEWTON'S LAWS OF MOTION & FRICTION

    MOTION|Exercise Problem|26 Videos

  • MODERN PHYSICS -1

    MOTION|Exercise EXERCISE-4 ( LEVEL- II)|39 Videos

  • NLM & FRICTION

    MOTION|Exercise EXERCISE-4 ( LEVEL-II)|15 Videos

Similar Questions

Explore conceptually related problems

A bullet of mass 0.03 kg moving with a speed of 400m/s penerates 12 cm into fixed block of wood. Calculate the average force exerted by the wood on the bullet.

A bullet of mass m moving with velocity upsilon_(1) strikes a suspended wooden block of mass M as shown in the figure and sticks to it. If the block rises to a height y. the initial of the bullet is

Knowledge Check

  • A bullet of mass m moving with velocity v strikes a suspended wooden block of mass M. If the block rises to a height h, the initial velocity of the block will be

    A
    ` sqrt( 2gh ) `
    B
    ` (M+m)/( m) sqrt( gh ) `
    C
    ` ( m )/( M+m) 2gh `
    D
    ` (M+m)/( M) sqrt( 2gh) `

  • A bullet of mass m moving with velocity v strikes a suspended wooden block of mass M . If the block rises to a height h , the initial velocity of the block will be (

    A
    `sqrt(2gh)`
    B
    `(M+m)/(m)sqrt(2gh)`
    C
    `(m)/(M+m)2gh`
    D
    `(M+m)/(M)sqrt(2gh)`

  • A bullet of mass 10 gm moving with a horizontal velocity 100m//s passes through a wooden block of mass 100 gm. The block is resting on a smooth horizontal floor. After passing through the block the velocity of the bullet is 10m//s . the velocity of the emerging bullet with respect to the block is

    A
    `10 m//s`
    B
    `9 m//s`
    C
    `1 m//s`
    D
    `5 m//s`

    • Similar Questions

    Explore conceptually related problems

    A bullet of mass 50g moving with velocity 600m//s hits block of mass 1.0kg placed on a rough horizontal ground and comes out of the block with a velocity of 400m//s . The coefficient of friction between the block and the ground is 0.25 . Neglect loss of mass of the block as the bullet pierces through it. (a) In spite of the fact that friction acts a an external force, can you apply principle of conservation of momentum during interaction of the ullet with the block? (b) Find velocity of the block immediately after the bullet pierces through it. (c)FInd the distance the block will travel before it stops.

    A bullet of mass 10gm moving with a horizontal velocity 100m//s passes through a wooden block of mass 100gm . The block is resting on a smooth horizontal floor. After passing through the block the velocity of the bullet is 10m//s the velocity of the emerging bullet with respect to the block is .

    A system of two blocks A and B are connected by an inextensible massless string as shown in Fig. The pulley is massless and frictionless. Initially, the system is at rest. A bullet of mass m moving with a velocity u as shown hits block If and gets embedded into it. The impulse imparted by tension force to the block of mass 3m is

    A 10 g bullet moving at 200 m/s stops after penetrating 5 cm of wooden plank. The average force exerted by the bullet will be

    . A bullet moving with a velocity of 200 cm / s penetrates a wooden block and comes to rest after traversing 4 cm inside it. What velocity is needed for travelling distance of 9cm in same block

    Home
    Profile