Home
Class 12
PHYSICS
A chain has five rings. The mass of each...

A chain has five rings. The mass of each ring is 0.1 kg. This chain is pulled upwards by a froce F producing an acceleration of 2.50 m/sec2 in the chain. Then the force of action (reaction) on the joint of second and third ring from the top is -

A

0.25 N

B

1.23 N

C

3.69 N

D

6.15 N

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Topper's Solved these Questions

  • NEWTON'S LAWS OF MOTION & FRICTION

    MOTION|Exercise Exercise - 1 SECTION-C :- Pseudo force, Weighing Machine|11 Videos
  • NEWTON'S LAWS OF MOTION & FRICTION

    MOTION|Exercise Exercise - 1 SECTION-D :- Spring force and spring cutting problems|7 Videos
  • NEWTON'S LAWS OF MOTION & FRICTION

    MOTION|Exercise Exercise - 1 (SECTION-A:- String Constrained, Wedge Constrained, Newtons Law theory Question, Equillibrium Questions (Normal and Tension), Problems with Acceleration (F=ma), Wedge problems)|27 Videos
  • MODERN PHYSICS -1

    MOTION|Exercise EXERCISE-4 ( LEVEL- II)|39 Videos
  • NLM & FRICTION

    MOTION|Exercise EXERCISE-4 ( LEVEL-II)|15 Videos

Similar Questions

Explore conceptually related problems

A chain consisting of 5 links each of mass 0.1 kg is lifted vertically with a constant acceleration of 2.5 m//s^(2) as shown in the figure. The force of interaction between the top link and the link immediately below it, will be

A body of mass 8 kg is hanging from another body of mass 12 kg. The combination is being pulled up by a string with an acceleration of 2.2 m/sec2. The tension T1 will be -

A chain consisting of 5 links each of mass d 0.1 kg is lifted vertically up with a constant acceleration of 2.5m//s^(2) .The force of interaction between 1st and 2nd links as shown

A chain consisting of 5 links each of mass 0.1kg is lifted vertically with a constant acceleration of 2m//s^(2) as shown in The force of interaction (in newton) between the top link and the link immediately below it will be Take g = 10m//s^(2) .

A boy is pushing a ring of mass 2kg and radius 0.5 m with a stick as shown in figure. The stick applies a force of 2N on the ring and rolls it without slipping with an acceleration of 0.3 m/s^2. The coefficient of friction between the ground and the ring is large enough that rolling always occurs and the coefficient of friction between the stick and the ring of (P/10). The value of P is

In a ring of mass 0.5 kg and radius sqrt(5) m, to produce angular acceleration of 18rad//s^(2) in this body, applied torque (in N-m) should be