Calculate the energy of photon having ` lamda = 4000 Å ` in eV and in Joule

Explanation

To calculate the energy of a photon with a wavelength of \( \lambda = 4000 \, \text{Å} \) (angstroms), we can use the formula for the energy of a photon:

\[ E = \frac{hc}{\lambda} \]

where:
- \( E \) is the energy of the photon,
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