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The work function of a metal is 4 eV...

The work function of a metal is 4 eV if 5000 Å wavelength of light is incident on the metal. Is there any photo electric effect ?

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To determine whether there is a photoelectric effect when light of a certain wavelength strikes a metal, we need to compare the energy of the incident photons with the work function of the metal. Here’s a step-by-step solution: ### Step 1: Understand the Work Function The work function (Φ) of a metal is the minimum energy required to remove an electron from the surface of that metal. In this case, the work function is given as 4 eV. ### Step 2: Calculate the Energy of the Incident Light The energy (E) of a photon can be calculated using the formula: \[ E = \frac{hc}{\lambda} \] Where: - \( h \) is Planck's constant (\( 4.1357 \times 10^{-15} \) eV·s), - \( c \) is the speed of light (\( 3 \times 10^8 \) m/s), - \( \lambda \) is the wavelength of the light in meters. Since the wavelength is given in angstroms (Å), we convert it to meters: \[ 5000 \, \text{Å} = 5000 \times 10^{-10} \, \text{m} = 5 \times 10^{-7} \, \text{m} \] Now, substituting the values into the energy formula: \[ E = \frac{(4.1357 \times 10^{-15} \, \text{eV·s}) \times (3 \times 10^8 \, \text{m/s})}{5 \times 10^{-7} \, \text{m}} \] ### Step 3: Simplify the Calculation Calculating the energy: \[ E = \frac{(4.1357 \times 3) \times 10^{-7} \, \text{eV·m}}{5} \] \[ E = \frac{12.4071 \times 10^{-7}}{5} \] \[ E = 2.48142 \, \text{eV} \] ### Step 4: Compare the Energy with the Work Function Now, we compare the calculated energy of the incident light with the work function: - Energy of incident light = 2.48 eV - Work function = 4 eV Since \( 2.48 \, \text{eV} < 4 \, \text{eV} \), the energy of the incident light is less than the work function of the metal. ### Step 5: Conclusion Because the energy of the incident photons is less than the work function, no electrons will be emitted from the metal surface. Therefore, there will be no photoelectric effect. ### Final Answer **No, there is no photoelectric effect.** ---
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