Home
Class 12
PHYSICS
The acceleration due to gravity is 9.8 m...

The acceleration due to gravity is `9.8 m s^(-2)`. Give its value in ft `s^(-2)`

Text Solution

Verified by Experts

As `1m=3.2` ft
`:.9.8 m//s^(2)=9.8xx3.28"ft"//s^(2)=32.14"ft"//s^(2)~~32 "ft"//s^(2)`
Promotional Banner

Topper's Solved these Questions

  • UNITS AND DIMENSIONS, BASIC MATHEMATICS

    MOTION|Exercise Exercise - 1 (Objective Problems) (SECTON-A:- UNIT AND DIMENSION )|20 Videos

  • UNITS AND DIMENSIONS, BASIC MATHEMATICS

    MOTION|Exercise Exercise - 1 (Objective Problems) (SECTION - B : Dimension and use of dimensions )|28 Videos

  • UNIT & DIMENSIONS

    MOTION|Exercise Exercise - 4 (Level - II) (PREVIOUS YEAR JEE ADVANCED)|10 Videos

  • VECTOR

    MOTION|Exercise Exercise - 3|18 Videos

Similar Questions

Explore conceptually related problems

The acceleration due to gravity is 9.8m//s^(2)

Taking the value of the acceleration due toj gravity as 10 m s^(-2) , Find its value in km h^(-2).

The value of acceleration due to gravity at a place is 9.8ms^(-2) . Find its value in km h^(-2)

The value of acceleration due to gravity is 980 cm s^(-2) . What will be its value if the unit of length is kilometer and that of time is minute?

The acceleration due to gravitiy is "9.8 ms"^(-2) . Give its dimensional formula.

The value of acceleration due to gravity

The value of acceleration due to gravity is 980 cm//sec^2 .What will be its value if the unit of length is kilometer and that of time is hour ?

Suppose the acceleration due to gravity at a place is 10 m/s^2 . Find its value in cm//(minute).

A car is moving along a horizontal curve of radius 20 m , and coefficient of friction between the road and wheels of the car is 0.25 . If acceleration due to gravity is (9.8 m//s^(2)) , then its maximum speed is