Give the order of the following :
Gravitational constant
(`6.67xx10^(-11)N-m^(2)//kg^(2)`)

Answer

To find the order of the gravitational constant given as \( 6.67 \times 10^{-11} \, \text{N m}^2/\text{kg}^2 \), we can follow these steps:

### Step 1: Identify the value of \( a \) and \( b \)
In the expression \( a \times 10^b \), we have:
- \( a = 6.67 \)
- \( b = -11 \)

### Step 2: Determine the condition for \( a \)
Since \( a = 6.67 \), we note that:
- \( a \) is greater than 5.

### Step 3: Apply the rule for finding the order
According to the rule:
- If \( a \) is greater than or equal to 5, the order is given by \( b + 1 \).

### Step 4: Calculate the order
Since \( b = -11 \):
- The order will be \( -11 + 1 = -10 \).

### Final Answer
Thus, the order of the gravitational constant \( 6.67 \times 10^{-11} \, \text{N m}^2/\text{kg}^2 \) is \( -10 \).

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