Give the order of the following :
Radius of H– atom (`5.29xx10^(-11)m`)

Answer

To find the order of the radius of the H- atom given as \(5.29 \times 10^{-11} \, \text{m}\), we will follow these steps:

### Step-by-Step Solution:

1. **Identify the given value**: The radius of the H- atom is given as \(5.29 \times 10^{-11} \, \text{m}\).

2. **Express in scientific notation**: The value is already expressed in scientific notation, which is of the form \(a \times 10^n\), where \(1 \leq a < 10\) and \(n\) is an integer.

3. **Determine the exponent**: In this case, the exponent \(n\) is \(-11\).

4. **Check the coefficient**: The coefficient \(5.29\) is greater than \(5\). According to the rules of order of magnitude, if the coefficient is greater than or equal to \(5\), we round up the exponent.

5. **Calculate the order of magnitude**: Since \(5.29\) is greater than \(5\), we add \(1\) to the exponent:
\[ -11 + 1 = -10 \]

6. **Final result**: Therefore, the order of the radius of the H- atom is \(10^{-10}\).

### Conclusion:
The order of the radius of the H- atom is \(10^{-10} \, \text{m}\).

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