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Given R(1) = 5.0 +- 0.2 Omega, and R(2) ...

Given `R_(1) = 5.0 +- 0.2 Omega, and R_(2) = 10.0 +- 0.1 Omega`. What is the total resistance in parallel with possible `%` error?

Text Solution

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The correct Answer is:
`R_(s)=15` ohm `pm 2%; R_(p)=3.3` ohm `pm 7%`
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