Home
Class 12
PHYSICS
The values of two resistors are R(1)=(6+...

The values of two resistors are `R_(1)=(6+-0.3)kOmega` and `R_(2)=(10+-0.2)kOmega`. The percentage error in the equivalent resistance when they are connected in parallel is

A

`5.125%`

B

0.02

C

`10.125%`

D

0.07

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Topper's Solved these Questions

  • UNITS AND DIMENSIONS, BASIC MATHEMATICS

    MOTION|Exercise Exercise - 3 ( Section-A Previous Year Problems )|29 Videos
  • UNITS AND DIMENSIONS, BASIC MATHEMATICS

    MOTION|Exercise Exercise - 3 ( Section-B Previous Year Problems )|10 Videos
  • UNITS AND DIMENSIONS, BASIC MATHEMATICS

    MOTION|Exercise Exercise - 1 (Objective Problems) (SECTION - D :- ERRORS )|19 Videos
  • UNIT & DIMENSIONS

    MOTION|Exercise Exercise - 4 (Level - II) (PREVIOUS YEAR JEE ADVANCED)|10 Videos
  • VECTOR

    MOTION|Exercise Exercise - 3|18 Videos

Similar Questions

Explore conceptually related problems

Two resistor R_(1) = (24 +- 0.5)Omega and R_(2) = (8 +- 0.3)Omega are joined in series, The equivalent resistence is

Two resistor of resistance R_(1)=(6+-0.09)Omega and R_(2)=(3+-0.09)Omega are connected in parallel the equivalent resistance R with error (in Omega)

Two resistance R_(1)=100pm 3Omega and R_(2)=200pm4Omega are connected in seriesg. What is their equivalent resistance?

Two resistors of resistances R_(1)=(300+-3) Omega and R_(2)=(500+-4) Omega are connected in series. The equivalent resistance of the series combination is

Two resistances R_(1) = 100 +- 3 Omega and R_(2) = 200 +- 4 Omega are connected in series . Find the equivalent resistance of the series combination.

Two resistors R_1 = (4 pm 0.8) Omega and R_2 (4 pm 0.4) Omega are connected in parallel. The equivalent resistance of their parallel combination will be :

Given Resistance R_(1) = (8 +- 0.4) Omega and Resistence, R_(2) = (8 +- 0.6) Omega What is the net resistence when R_(1) and R_(2) are connected in series?

108 . If two resistors of resistances R_(1)= (4 +- 0.5 )Omega and R_(2) =(16+-0.5)Omega are connected (i) in series and (ii) in parallel, find the equivalent resistance in each case with limits of percentage error.

Two carbon resistances are given by R_(1)=(4pm0.4) ohm and R_(2)=(12pm0.6)Omega . What is their net resistance with percentage error, if they are connected in series?

MOTION-UNITS AND DIMENSIONS, BASIC MATHEMATICS -Exercise - 2 (Objective Problems )
  1. Which of the following system of units is not based on units of mass, ...

    Text Solution

    |

  2. Which of the following quantity is unitless ?

    Text Solution

    |

  3. The dimensional formula of wave number is

    Text Solution

    |

  4. Which of the following does not have the dimensions of force?

    Text Solution

    |

  5. Which of the following is incorrect statement

    Text Solution

    |

  6. A dimensionless quantity

    Text Solution

    |

  7. A unitless quantity

    Text Solution

    |

  8. Which of the following is incorrect

    Text Solution

    |

  9. The Bernoulli's equation is given by P+1/2 rho v^(2)+h rho g=k. Where ...

    Text Solution

    |

  10. When a wave transverses in a medium, the displacement of a particle lo...

    Text Solution

    |

  11. The method of dimensional analysis can be used to derive which of the ...

    Text Solution

    |

  12. If the error in the measurement of radius of a sphere in 2% then the e...

    Text Solution

    |

  13. An iceberg of density 900kg//m^(3) is floating in water of density 100...

    Text Solution

    |

  14. A vernier calipers has 1mm marks on the main scale. It has 20 equal di...

    Text Solution

    |

  15. The diameter of a cylinder is measured using a Vernier callipers with...

    Text Solution

    |

  16. The percentage errors in the measurement of length and time period of ...

    Text Solution

    |

  17. A physical quantity A is related to four observable a,b,c and d as fol...

    Text Solution

    |

  18. The values of two resistors are R(1)=(6+-0.3)kOmega and R(2)=(10+-0.2)...

    Text Solution

    |

  19. The mass and volume of a body are found to be 5.00 pm 0.05 kg " and "...

    Text Solution

    |

  20. The VC shown in the diagram has zero error in it. It is given that 9 m...

    Text Solution

    |