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A rectangular loop sides 10 cm and 3 cm ...

A rectangular loop sides 10 cm and 3 cm moving out of a region of uniform magnetic field of 0.5T directed normal to the loop. If we want to move loop with a constant velocity `1 cm//sec`. Then required mechanical force is (Resistance of loop =`1mOmega`):-

A

`2.25xx10^(-3)N`

B

`4.5xx10^(-3)N`

C

`9xx10^(-3)N`

D

`1.25xx10^(-3)N`

Text Solution

Verified by Experts

The correct Answer is:
A
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