An inductor of inductance `L=400mH` and resistors of resistances `R_(1)=2 Omega` and `R_(2)=2 Omega` are connected to a battery of `emf 12 V` as shown in figure.The internal resistance of the battery is negligible.The switch `S` is closed at `t=0`.The potential drop across `L` as a function of time is:

Options

A. `6e^(-5t)V`
B. `(12)/(t)e^(-3t)V`
C. `6[1-e^(-t//0.2))V`
D. `12 e^(-5tV`

Answer

d