Home
Class 12
PHYSICS
The displacement x of a particle moving ...

The displacement x of a particle moving in one dimension under the action of a constant force is related to time t by the equation `t=sqrt(x)+3`, where x is in meter and t is in second. Find the displacement of the particle when its velocity is zero.

A

0

B

3m

C

`-3m`

D

2m

Text Solution

Verified by Experts

Given ` t = sqr(x) + 3 rArr x = t^(2) - 6t + 9 rArr (dx)/(dt) = 2t - 6`
` rArr ` Instantaneous velocity, ` v = (dt)/(dx) = 2t – 6`
when `v = 0, 2t – 6 = 0 rArr t = 3 sec` . Thus at t = 3
sec,` x = (t^(2) – 6t + 9) = 0`
Hence correct answer is (A).
Promotional Banner

Topper's Solved these Questions

  • ONE DIMENSION MOTION

    MOTION|Exercise EXERCSE -1 (Section - A : Distance, Displacement, Velocity and Acceleration, Equation of Motion )|26 Videos
  • ONE DIMENSION MOTION

    MOTION|Exercise EXERCSE -1 (Section - B : Motion under Gravity)|11 Videos
  • NLM & FRICTION

    MOTION|Exercise EXERCISE-4 ( LEVEL-II)|15 Videos
  • OPTICS

    MOTION|Exercise Exercise|45 Videos

Similar Questions

Explore conceptually related problems

The displacement x of a particle moving in one dismension under the action of a constant force is frlated to time t by the equation tsqrtx+3 , where x is in merers and t is in seconds, Find the displacemect of the particle when its velocity is zero.

The distance x of a particle moving in one dimensions, under the action of a constant force is related to time t by the equation, t=sqrt(x)+3 , where x is in metres and t in seconds. Find the displacement of the particle when its velocity is zero.

The displacement x of particle moving in one dimension, under the action of a constant force is related to the time t by the equation t = sqrt(x) +3 where x is in meters and t in seconds . Find (i) The displacement of the particle when its velocity is zero , and (ii) The work done by the force in the first 6 seconds .

The distance (x) particle moving in one dismension, under the action of a constant force is related to time (t) by equation tsqrt x +3 where (x) is in vettres and (t) in seconds. Find the displacement of the particle when its velcity is zero.

The displacement x of a particle of mass 1.0 kg moving the one dimension under the action of a force is related to time t by the equation t=sqrt(x)+5 where x is in meter and t is in second. The magnitude of the momentum of the particle

The displacement x of a particle of mass m kg moving in one dimension, under the action of a force, is related to the time t by the equation t=4x+3 where x is in meters and t is in seconds. The work done by the force in the first six seconds in joules is

The displacement 'x' (in meter) of a particle of mass 'm' (in kg) moving in one dimension under the action of a force is released to time 't' (in sec) by t = sqrt(x) + 3 . The displacement of the particle when its velocity is zero will be.

The displacement x in meters of a particle of mass m kg moving in one dimension under the action of a force is related to the time t in seconds by the equation t=sqrtx+3 , , the work done by the force (in J) in first six seconds is :-